Triangular prism volume7/6/2023 ![]() ![]() Then, by the triangular prism volume formula above. Let $V_A$ be the volume of the truncated triangular prism over right-triangular base $\triangle BCD$ likewise, $V_B$, $V_C$, $V_D$. So, let's explore the subdivided prism scenario:Īs above, our base $\square ABCD$ has side $s$, and the depths to the vertices are $a$, $b$, $c$, $d$. OP comments below that the top isn't necessarily flat, and notes elsewhere that only an approximation is expected. You will have to read all the given answers and click over. The volume of that figure $s^2h$ is twice as big as we want, because the figure contains two copies of our target.Įdit. Following quiz provides Multiple Choice Questions (MCQs) related to Volume of a Triangular Prism. This follows from the triangular formula, but also from the fact that you can fit such a prism together with its mirror image to make a complete (non-truncated) right prism with parallel square bases. Let the base $\square ABCD$ have edge length $s$, and let the depths to the vertices be $a$, $b$, $c$, $d$ let $h$ be the common sum of opposite depths: $h := a c=b d$. If the table-top really is supposed to be flat. Where $A$ is the volume of the triangular base, and $a$, $b$, $c$ are depths to each vertex of the base. ("Depths" to opposite vertices must sum to the same value, but $30 80 \neq 0 120$.) If we allow the table-top to have one or more creases, then OP can subdivide the square prism into triangular ones and use the formula The question statement suggests that OP wants the formula for the volume of a truncated right-rectangular (actually -square) prism however, the sample data doesn't fit this situation. ![]()
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